You’ve probably heard — or even taught — the classic rule:
·
If the mean is less than the median, the distribution is skewed to the
left;
·
If the mean is greater than the median, the skewness is to the right;
·
If mean, median, and mode coincide, the distribution is symmetric.
This rule works in
many situations... but it’s not universal. Relying on it too blindly can
lead to serious mistakes, even with small, simple, unimodal distributions.
📊 A numerical example
Consider this dataset:
0; 0; 0; 0.5; 0.5; 1.05; 1.25
Let’s break it down:
·
Mode: 0
·
Median: 0.5
·
Mean: approximately 0.471
The mean is less
than the median, which would suggest left skewness.
But when we compute
the skewness coefficient (based on the 3rd moment):
·
Skewness ≈ +0.59, meaning positive skewness → right-skewed distribution!
🔹 So what’s going on?
The mean–median–mode
rule only holds under ideal conditions, such as:
·
Continuous distributions;
·
Smooth shapes (no jumps or plateaus);
·
Well-behaved unimodal structure;
·
No outliers that pull the mean disproportionately.
Our example is small
and discrete. The mode has little “weight,” and two larger values pull the mean
upward, producing positive skewness, even though the mean is less than
the median.
🤔 A student's question
A student once asked:
“Can the mean be less
than the median, and yet the skewness be positive?”
The answer is: yes.
And not only is it possible — it’s quite common in small samples or discrete
distributions.
📅 The takeaway
Don’t use the position
of the mean alone to assess skewness.
Statistical skewness
reflects deeper aspects of the distribution — such as central moments or
the overall shape of the histogram.
🔹 It's better to
compute the skewness coefficient than to rely blindly on a rule of
thumb.
Reference
1. von HIPPEL, P. T. Mean, median and
skew: correcting a textbook rule. The Ohio State University. Journal od
Statistics Education. 13(2): 2005.
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